Home
Class 12
PHYSICS
Light of intensity 10^(-5)Wm^(-2) falls ...

Light of intensity `10^(-5)Wm^(-2)` falls on a sodium photocell of surface area `2cm^(2)`. Assuming that the top 5 layers of sodium absorb the incident energy, estimate the time required for photoelectric emission in the wave picture of radiation. The work function of the metal is given to be about 2eV. What is the implication of your answer? effective atomic area `=10^(-20)m^(2)`.

A

(10)1/2s

B

(1/2)s

C

(1/2)h

D

(1/2)yr

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Similar Questions

Explore conceptually related problems

Light of wavelength 4000 Å is incident on a metal surface. The maximum kinetic energy of emitted photoelectron is 2 eV. What is the work function of the metal surface ?

Calculate the kinetic energy of a photoelectron (in eV) emitted on shining light of wavelength 6.2 xx 10^(-6)m on a metal surface. The work function of the metal is 0.1 eV ?

Light strikes a sodium surface, causing photoelectric emission. The stopping potential for the ejected electrons is 5.0 V, and the work function of sodium is 2.2 eV. What is the wavelength of the incident light?

Two photons, each of energy 2.5 eV are simultaneously incident on the metal surface. If the work function of the metal is 4.5 eV, then from the surface of metal

The work function of lithium is 2.5 eV. what is the maximum wavelength of light that can cause the photoelectric effect in lithium?

Light of frequency 10^(15) Hz falls on a metal surface of work function 2.5 eV. The stopping potential of photoelectrons in volts is

What is the energy of emitted photoelectrons is light of frequency 10^(16) Hz is incident on a sodium target ? Work function of sodium is = 2.5 eV.