The shortest wavelength in balmer series...

The shortest wavelength in balmer series for hydrogen atom is .....A.... and this is obtained by substituting ,...B.... in balmer's formula. here A and B refer to

A

656.3 nm n=3

B

486.1 nm n=4

C

410.2 nm n=5

D

364.6 nm `n=infty`

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The correct Answer is:

D

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