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In case of beta positive (beta^+) decay,...

In case of beta positive `(beta^+)` decay, a position is emitted along with

A

an electron

B

a neutrino

C

an antineutrino

D

a positron

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The correct Answer is:
In beta positive decay (β+ decay), a positron is emitted along with a neutrino. Let's break down the process step by step: ### Step-by-Step Solution: 1. **Understanding Beta Positive Decay**: - Beta positive decay occurs when a proton in a nucleus is transformed into a neutron, emitting a positron and a neutrino in the process. 2. **Changes in Atomic Structure**: - When an element undergoes beta positive decay, its atomic number decreases by 1 (since a proton is converted into a neutron), but its mass number remains unchanged. - This can be represented as: \[ \text{X}^{A}_{Z} \rightarrow \text{Y}^{A}_{Z-1} + \beta^{+} + \nu \] - Here, X is the original element, Y is the new element formed, \( A \) is the mass number, \( Z \) is the atomic number, \( \beta^{+} \) is the emitted positron, and \( \nu \) is the emitted neutrino. 3. **Identifying Emissions**: - In the decay process, two key particles are emitted: - A **positron** (\( \beta^{+} \)): This is the antimatter counterpart of an electron. - A **neutrino** (\( \nu \)): This is a nearly massless and chargeless particle that carries away some energy and momentum. 4. **Example of Beta Positive Decay**: - Consider the decay of potassium-40 (\( \text{K}^{40}_{19} \)): \[ \text{K}^{40}_{19} \rightarrow \text{Ar}^{40}_{18} + \beta^{+} + \nu \] - In this example, potassium-40 decays to argon-40, emitting a positron and a neutrino. 5. **Conclusion**: - Therefore, in beta positive decay, a positron is emitted along with a neutrino. ### Final Answer: In case of beta positive decay, a positron is emitted along with a neutrino.
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