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From fission reaction of 92^235 U, on an...

From fission reaction of `_92^235` U, on an average number of neutrons (per fission) released is

A

1

B

2

C

3

D

2.5

Text Solution

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The correct Answer is:
D
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In a particular fission reaction, a ._92U^(235) nucleus captures a slow neutron. The fission products are three neutrons, a ._57La^(142) nucleus and a fission product ._ZX^A . What is the value of Z?

If 200 MeV of energy is released in the fission of 1 nucleus of ._(92)U^(235) , the number of nuclei that undergo fission to produce energy of 10 kWh in 1 s is

The fission properties of ._94^239Pu are very similar to those of ._92^235 U. The average energy released per fission is 180 MeV. If all the atoms in 1 kg of pure ._94^239Pu undergo fission, then the total energy released in MeV is

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(a) Calculate the energy released by the fission of 2g of ._(92)U^(235) in kWh . Given that the energy released per fission is 200MeV . (b) Assuming that 200MeV of enrgy is released per fission of uranium atom, find the number of fissions per second required to released 1 kilowatt power. (c) Find the amount of energy produced in joules due to fission of 1g of ._(92)U^(235) assuming that 0.1% of mass is transformed into enrgy. ._(92)U^(235) = 235 amu , Avogadro number = 6.023 xx 10^(23)

Two other possible ways by which .^(235)U can undergo fission when bombarded with a neutron are (1) by the release of .^(140)Xe and .^(94)Sr as fission fragments and (2) by the release of .^(132)Sn and .^(101)Mo as fission fragments. In each case, neutrons are also released. Find the number of neutrons released in each of these events.

The fission properties of ._84Pu^(239) are very similar to those of ._92U^(235) . The average energy released per fission is 180MeV . How much energy in MeV is released if all the atoms in 1kg of pure ._94Pu^(239) undergo fission.