Home
Class 12
PHYSICS
Taking Rydberg's constant R(H) = 1.097 x...

Taking Rydberg's constant `R_(H) = 1.097 xx 10^(7)m` first and second wavelength of Balmer series in hydrogen spectrum is

A

`2000overset@Aunderset",3000overset@A`

B

`1575overset@Aunderset",2960overset@A`

C

`6529overset@Aunderset",4280overset@A`

D

`6562overset@Aunderset",4863overset@A`

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Similar Questions

Explore conceptually related problems

Given the value of Rydberg constant is 10^(7)m^(-1) , the waves number of the lest line of the Balmer series in hydrogen spectrum will be:

Assuming Rydberg’s constant ( R_H ) to be 109670 cm^(–1) , the longest wavelength line in the Lyman series of the hydrogen spectrum (in Å) is:

The line with smallest wavelength in the Balmer series in the hydrogen spectrum will have the frequency :-

The wave number of the H_(a)- line in Balmer series of hydrogen spectrum is

What is maximum wavelength of line of Balmer series of Hydrogen spectrum (R=1.09 xx10^(7)m^(-1) ):

In terms of Rydberg constant R , the shortest wavelength in the Balmer series of the hydrogen , atom spestrum will have wavelength

Ratio of longest wavelengths corresponding to Lyman and Balmer series in hydrogen spectrum is

The Rydberg constant for hydrogen is 1.097xx10^(7)m^(-1) . Calculate the short and long wavelength limits of Lyman series.