Recommended Questions
- ಈ ಕೆಳಗಿನವುಗಳು ವರ್ಗ ಸಮಿಕರಣಗಳೇ ಎಂಬುದನ್ನು ಪರೀಕ್ಷಿಸಿ. (2x-1) (x-3) =(x+5) ...
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- Solve ((2x+1)!)/((x+2)!)xx((x-1)!)/((2x-1)!)=(3)/(5)(x in N)
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- Prove that :(log)e((x+1)/x)=2[1/((2x+1))+1/(3(2x+1)^3)+1/(5(2x+1)^5)+]
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- (2x + 3) / (2x + 5)-(x) / (x + 1) = (1) / (2x + 3), (x! = -1, x! =-(5)...
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- If f(x)=||x-1|+|x-3|-|2x-1||+||x-1|+|x-3|+|2x-1|| , then
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- If |[2x, x+3], [2(x+1), x+1]| = |[1, 5], [3, 3]|, find the value of x.
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- Solve: 2((2x-1)/(x+3))-3((x+3)/(2x-1))=5,xne-3,(1)/(2).
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- Solve : ((2x+1)!)/((x+2)!)xx((x-1)!)/((2x-1)!)=(3)/(5),( x in N N)
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- (2x-1)/((x-1)(2x+3))=1/(5(x-1))-k/(5(2x+3)), then k =
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