Oxidation number of oxygen in `H_(2)O_(2)` is:

Options

A. `-1`
B. `+1`
C. `-2`
D. `+2`

Explanation

To find the oxidation number of oxygen in hydrogen peroxide (H₂O₂), we can follow these steps:

### Step 1: Write the chemical formula and identify the elements
The chemical formula for hydrogen peroxide is H₂O₂. In this compound, we have:
- Hydrogen (H)
- Oxygen (O)

### Step 2: Assign oxidation numbers to known elements
In most compounds:
- The oxidation number of hydrogen is +1.
- The oxidation number of oxygen is typically -2, but we need to determine it in this case.

### Step 3: Set up the equation based on the overall charge
Since H₂O₂ is a neutral molecule, the sum of the oxidation numbers must equal zero. Let the oxidation number of oxygen be represented as \( x \).

The equation can be set up as follows:
\[ \text{Sum of oxidation numbers} = 2(\text{oxidation number of H}) + 2(\text{oxidation number of O}) = 0 \]
Substituting the known values:
\[ 2(+1) + 2(x) = 0 \]

### Step 4: Simplify the equation
Now, simplify the equation:
\[ 2 + 2x = 0 \]

### Step 5: Solve for x
To isolate \( x \), we can rearrange the equation:
\[ 2x = -2 \]
Now, divide by 2:
\[ x = -1 \]

### Conclusion
The oxidation number of oxygen in H₂O₂ is -1.