Which compound gives iodoforms by reactions between`l_(2)` and `NaOH` ?

Options

A. `CH_(3)OH`
B. `C_(2)H_(5)OH`
C. `C_(3)H_(7)OH`
D. `C_(2)H_(5) - O-C_(2)H_(5)`

Explanation

To determine which compound gives iodoform upon reaction with iodine (I2) and sodium hydroxide (NaOH), we need to understand the conditions required for the iodoform test.

### Step-by-Step Solution:

1. **Understanding the Iodoform Test**:
The iodoform test is used to identify the presence of a methyl ketone (a ketone with the structure R-CO-CH3) or a secondary alcohol that can be oxidized to a methyl ketone. The reaction involves iodine and a base (like NaOH).

2. **Identifying the Structure**:
For a compound to give a positive iodoform test, it must have a structure that includes:
- A methyl group (CH3) adjacent to a carbonyl group (C=O) or
- A secondary alcohol that can be oxidized to a methyl ketone.

3. **Examples of Compounds**:
- Methyl ketones like acetone (CH3-CO-CH3) will give a positive iodoform test.
- Secondary alcohols like isopropanol (CH3-CHOH-CH3) will also give a positive test after oxidation.

4. **Reaction Mechanism**:
When a suitable compound is treated with I2 and NaOH, the methyl group adjacent to the carbonyl or hydroxyl group will react to form iodoform (CHI3), which is a yellow precipitate.

5. **Conclusion**:
The compound that gives iodoform upon reaction with I2 and NaOH is typically a methyl ketone or a secondary alcohol with the structure R-CO-CH3 or R-CHOH-CH3.

### Final Answer:
The compound that gives iodoform by reactions between I2 and NaOH is a methyl ketone or a secondary alcohol that can be oxidized to a methyl ketone.