On complete hydrolysis `XeF_(6)` gives:

Options

A. `XeO_(3) + 6HF`
B. `XeO_(3) + 2HF`
C. `XeOF_(4) + 2HF`
D. `XeOF_(4) + 4HF`

Explanation

To solve the question regarding the complete hydrolysis of \( XeF_6 \), we will follow a step-by-step approach.

### Step 1: Understanding Hydrolysis
Hydrolysis is a chemical reaction involving the breaking of a bond in a molecule using water. In the case of \( XeF_6 \), it will react with water to form other products.

### Step 2: Reaction of \( XeF_6 \) with Water
When \( XeF_6 \) undergoes hydrolysis, it reacts with water. The first step involves one mole of water reacting with \( XeF_6 \):

\[ XeF_6 + H_2O \rightarrow XeOF_4 + HF \]

### Step 3: Further Hydrolysis
The product \( XeOF_4 \) can further react with more water. In the second step, we add two moles of water:

\[ XeOF_4 + 2H_2O \rightarrow XeO_2F_2 + 2HF \]

### Step 4: Complete Hydrolysis
Continuing this process, we can add three more moles of water to \( XeO_2F_2 \):

\[ XeO_2F_2 + 3H_2O \rightarrow XeO_3 + 6HF \]

### Step 5: Final Product
After complete hydrolysis, the final product formed is \( XeO_3 \) along with \( 6HF \).

### Conclusion
Thus, on complete hydrolysis, \( XeF_6 \) gives:

\[ XeO_3 + 6HF \]

### Final Answer
The correct answer is \( XeO_3 + 6HF \).

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