Structure of a mixed oxide is cubic closed - packed (ccp) .The cubic unit cell of mixed oxide is composed of oxide ions .One fourth of the tetrahedral voids are occupied by divalent metal A and the octahedral voids are occupied by a monovelent metal B .The formula of the oxide is

Options

A. `A_(2)BO_(2)`
B. `ABO_(2)`
C. `A_(2)B_(3)O_(4)`
D. `AB_(2)O_(2)`

Answer

B

Explanation

`AB_(2)O_(2)`
Explanation : `O^(2-) = 8 xx (1)/(8) = 1`
`A = (1)/(4) xx 2 = (1)/(2) , B = 1`
So, `A_(1//2) BO rArr AB_(2)O_(2)` is formula .