When ethyl bromide reacts with silver cyanide, the main product will be:

Options

A. Ethyl cyanide
B. Ethyl isocyanide
C. Ethene
D. Ethanol

Explanation

To determine the main product when ethyl bromide reacts with silver cyanide, we can follow these steps:

### Step 1: Understand the Reactants
- Ethyl bromide (C2H5Br) is an alkyl halide where bromine is attached to an ethyl group (C2H5).
- Silver cyanide (AgCN) is a covalent compound that contains cyanide (CN-) as a ligand.

### Step 2: Identify the Mechanism of Reaction
- The reaction between ethyl bromide and silver cyanide involves nucleophilic substitution. The cyanide ion (CN-) acts as a nucleophile.
- Since silver cyanide is covalent, the cyanide ion will attack the carbon atom bonded to bromine.

### Step 3: Formation of the Carbocation
- When bromine leaves (as Br-), it creates a carbocation (C2H5+), which is a positively charged carbon atom.
- The cyanide ion will then attack this carbocation.

### Step 4: Nucleophilic Attack
- The nitrogen atom in the cyanide ion (CN-) has a lone pair of electrons, which allows it to attack the carbocation.
- The attack occurs at the carbon atom, leading to the formation of a new bond between the carbon and the nitrogen.

### Step 5: Product Formation
- The product formed from this reaction is ethyl isocyanide (C2H5N≡C), where the nitrogen is triple-bonded to the carbon.
- The reaction can be summarized as follows:
\[ \text{C2H5Br} + \text{AgCN} \rightarrow \text{C2H5N≡C} + \text{AgBr} \]

### Final Answer
The main product when ethyl bromide reacts with silver cyanide is **ethyl isocyanide (C2H5N≡C)**.

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