Complete the following analogy:
A: Substituting halogen B: Substitution alkane by alkoxy of haloalkane by amino group

Options

A. A: Finkelstein Reaction, B: Hundsdicekr reaction.
B. A: Darzen's method:B: Groove's method
C. A: Williamsons synthesis, B Hofmann ammono- lysis
D. A: Wurtz reaction, B: Frankland Reaction

Explanation

To complete the analogy provided in the question, we will analyze the two parts: A and B.

### Step-by-Step Solution:

1. **Understanding Part A: Substituting Halogen**
- In organic chemistry, substituting a halogen typically refers to a reaction where a halogen atom (like Cl, Br, or I) in a compound is replaced by another atom or group. This is often seen in reactions involving alkyl halides (haloalkanes).

**Hint:** Recall that halogens are good leaving groups in substitution reactions.

2. **Identifying the Reaction Type**
- The type of reaction that involves the substitution of a halogen can be classified as a nucleophilic substitution reaction. In this case, we can refer to the Williamson ether synthesis, where an alkoxide ion (RO-) acts as a nucleophile and displaces the halogen.

**Hint:** Think about how nucleophiles attack electrophiles in substitution reactions.

3. **Understanding Part B: Substitution of Alkane by Amino Group**
- In this part, we are looking at the substitution of an alkyl halide (like C2H5Br) with an amino group (NH2). This is known as the Hofmann Ammonolysis reaction, where the amino group replaces the halogen.

**Hint:** Consider how ammonia (NH3) can act as a nucleophile in this reaction.

4. **Establishing the Analogy**
- Now, we can complete the analogy:
- A: Substituting halogen (Williamson ether synthesis)
- B: Substitution of alkane by amino group (Hofmann Ammonolysis)

**Hint:** Identify the key reactions associated with each part of the analogy.

5. **Finalizing the Answer**
- Therefore, the completed analogy is:
- A: Williamson Ether Synthesis
- B: Hofmann Ammonolysis

### Final Answer:
A: Williamson Ether Synthesis
B: Hofmann Ammonolysis