An ether with molecular formula `C_5 H_(12)O` when heated with excess HI produced two alkyl iodide which on alkaline hydrolysis forms. compound (B) and (C), Oxidation of (8) give acid and oxidation of (C) give ketone. The compound A will be:

Options

A. `C_2H_5 OCH(CH_3)_2`
B. `C_2H_5 OCH_2 CH_2 CH_3`
C. `CH_2 OCH_2 CH_2 CH_2 CH_3`
D. `CH_3 OCH_2 CH_2 CHCH_3`

Explanation

To solve the problem step by step, we need to analyze the information provided in the question and the reactions described in the video transcript.

### Step 1: Identify the Ether
The molecular formula given is \(C_5H_{12}O\). This indicates that we have an ether. Ethers generally have the structure \(R-O-R'\). We need to find suitable \(R\) and \(R'\) that satisfy the molecular formula.

**Hint:** Consider common ethers with 5 carbons and 12 hydrogens.

### Step 2: Determine Possible Structures
One possible structure for the ether could be ethyl methyl ether, which can be represented as \(C_2H_5-O-CH_3\) (ethyl group and methyl group). This gives us a total of 5 carbons, 12 hydrogens, and 1 oxygen.

**Hint:** Check if the structure you propose matches the molecular formula.

### Step 3: Reaction with HI
When heated with excess HI, ethers undergo cleavage to form alkyl iodides. For ethyl methyl ether, the reaction would yield:
- Ethyl iodide (\(C_2H_5I\))
- Methyl iodide (\(CH_3I\))

**Hint:** Remember that excess HI leads to the formation of two alkyl iodides.

### Step 4: Alkaline Hydrolysis
Next, both alkyl iodides undergo alkaline hydrolysis.
- Ethyl iodide (\(C_2H_5I\)) will yield ethanol (\(C_2H_5OH\)).
- Methyl iodide (\(CH_3I\)) will yield methanol (\(CH_3OH\)).

So, we have:
- Compound B: Ethanol (\(C_2H_5OH\))
- Compound C: Methanol (\(CH_3OH\))

**Hint:** Alkaline hydrolysis replaces the iodide with an alcohol group.

### Step 5: Oxidation of Compounds
Now, we need to consider the oxidation of these compounds:
- Oxidation of ethanol (\(C_2H_5OH\)) can yield acetic acid (\(CH_3COOH\)).
- Oxidation of methanol (\(CH_3OH\)) can yield formaldehyde (\(HCHO\)) or further oxidized to formic acid (\(HCOOH\)).

**Hint:** Remember that primary alcohols can be oxidized to aldehydes or acids, while secondary alcohols can be oxidized to ketones.

### Step 6: Identify the Final Products
From the oxidation:
- Compound B (ethanol) gives acetic acid.
- Compound C (methanol) gives formaldehyde or formic acid.

**Hint:** Identify which products correspond to the oxidation of the compounds formed.

### Step 7: Conclusion
Given the reactions and the products formed, the original ether (Compound A) is ethyl methyl ether (\(C_2H_5-O-CH_3\)).

**Final Answer:** The compound A will be \(C_2H_5-O-CH_3\) (ethyl methyl ether).