`CH_3 Br underset("Dry ether")overset(Mg)to CH_2MgBr overset(D_2O)to B `

Options

A. `CH_3 MgBr and CH_3OH`
B. `CH_3 MgBr and CH_3D`
C. `CH_3 MgBr and CH_3OH`
D. `CH_3 MgBr and CH_4`

Explanation

To solve the given question step by step, we will analyze the chemical reactions involved.

### Step 1: Identify the Reactants
The first reactant is **CH₃Br** (Methyl Bromide) and the second reactant is **Mg** (Magnesium) in dry ether.

### Step 2: Formation of Grignard Reagent
When CH₃Br reacts with magnesium in dry ether, it forms a Grignard reagent. The reaction can be represented as follows:

\[ \text{CH}_3\text{Br} + \text{Mg} \xrightarrow{\text{Dry Ether}} \text{CH}_3\text{MgBr} \]

Here, **CH₃MgBr** is known as Methyl Magnesium Bromide, which is a Grignard reagent.

### Step 3: Reaction with D₂O
Next, we take the Grignard reagent **CH₃MgBr** and react it with **D₂O** (Deuterium Oxide). The reaction proceeds as follows:

\[ \text{CH}_3\text{MgBr} + \text{D}_2\text{O} \rightarrow \text{CH}_3\text{D} + \text{Mg(OD)Br} \]

In this reaction, the Grignard reagent reacts with D₂O, resulting in the formation of **CH₃D** (Methyl Deuteride) and magnesium bromide deuteroxide **Mg(OD)Br**.

### Step 4: Identify the Product
The final product formed from the reaction is **CH₃D**.

### Conclusion
Thus, the product B formed from the given reactions is **CH₃D**.

### Final Answer
The correct option is **CH₃D**.

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