If a is the length of the side of a cube, the distance between the body centred atom and one corner atom in the cube will be:

Options

A. `(2)/(sqrt(2))a`
B. `(sqrt(3))/(2) a`
C. `(4)/(sqrt(3))a`
D. `(sqrt(3))/(4)a`

Answer

B

Explanation

The total no. of atoms in bcc is 2. One atom tie at the centre of the cube while, other lies at the corner of the cube. Hence, the distance between the body centred and one corner atom is half of body diagonal, ie. `(sqrt(3))/(2)a`