Identify X in the following reaction `CH_3 - CH= CH_2 underset("H_2 O_2//OH^(-))overset(B_2 H_6)to 'X'`

Options

A. Propanone
B. Prapan-1-ol
C. Propanal
D. Propan-2-ol

Explanation

To identify the compound X in the reaction `CH3 - CH= CH2 underset("H2O2//OH^(-))overset(B2H6)to 'X'`, we will follow the steps of the hydroboration-oxidation reaction.

### Step-by-Step Solution:

1. **Identify the Starting Material**:
The starting material is propene (CH3-CH=CH2).

2. **Reagents Involved**:
The reagents used are B2H6 (diborane) for hydroboration and H2O2 with OH- for oxidation.

3. **Hydroboration Step**:
- In the hydroboration step, B2H6 adds across the double bond of propene. According to Markovnikov's rule, the boron atom (B) will attach to the less substituted carbon (the terminal carbon), while the hydrogen (H) will attach to the more substituted carbon.
- The addition of B2H6 to propene results in the formation of an organoborane intermediate.
- The reaction can be visualized as follows:
- Propene (CH3-CH=CH2) reacts with B2H6, leading to the formation of CH3-CH2-CH2-BH2.

4. **Oxidation Step**:
- The organoborane intermediate is then oxidized using H2O2 and OH-.
- During this oxidation, the boron atom is replaced by a hydroxyl group (OH).
- The oxidation of the intermediate CH3-CH2-CH2-BH2 leads to the formation of propanol (CH3-CH2-CH2-OH).

5. **Final Product**:
- The final product X is thus identified as propanol (or 1-propanol).

### Conclusion:
The compound X in the reaction is **propanol (C3H8O)**.