Which of the following reaction is not the evidence for presence of aldehyde:

Options

A. Reaction glucose with hycloroxylamine
B. Reaction of glucose with `Br_2` water
C. Reaction of glucose HCN
D. Reaction of glucose with acetyle chloride

Explanation

To determine which reaction is not evidence for the presence of an aldehyde, we need to analyze the reactions involving glucose and identify the one that does not indicate the presence of the aldehyde functional group (–CHO).

### Step-by-Step Solution:

1. **Understanding the Structure of Glucose**:
- Glucose is a six-carbon sugar with an aldehyde group. The structure can be represented as:
```
CHO-CHOH-CHOH-CHOH-CHOH-CH2OH
```
- The aldehyde group is at one end of the molecule.

2. **Identifying the Reactions**:
- We have several reactions to consider:
- Reaction with acetyl chloride
- Reaction with hydroxylamine
- Reaction with bromine water
- Reaction with hydrogen cyanide (HCN)

3. **Analyzing Each Reaction**:
- **Reaction with Acetyl Chloride**:
- This reaction forms acetyl derivatives of glucose. It primarily reacts with the alcoholic groups present in glucose, rather than the aldehyde group. Thus, it does not provide direct evidence for the presence of the aldehyde group.

- **Reaction with Hydroxylamine**:
- Hydroxylamine reacts with aldehydes to form oximes. This reaction is a clear indication of the presence of the aldehyde group.

- **Reaction with Bromine Water**:
- Bromine water reacts with aldehydes to produce carboxylic acids. This reaction also confirms the presence of the aldehyde group.

- **Reaction with Hydrogen Cyanide (HCN)**:
- HCN reacts with aldehydes to form cyanohydrins, which is another indication of the presence of the aldehyde group.

4. **Conclusion**:
- Among the reactions analyzed, the reaction with acetyl chloride does not provide evidence for the presence of the aldehyde group, as it primarily indicates the presence of alcoholic groups instead.

### Final Answer:
The reaction that is not evidence for the presence of an aldehyde is the **reaction with acetyl chloride**.

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