Which of the following alcohol is obtained when. 2-methyl propene reacts with `H_(2)O` in presence of `H_(2)SO_(4)` :

Options

A. isobutyl alcohol
B. sec. butyl alcohot
C. tert, butyl alcohol
D. n-butyl alcohol

Answer

To solve the problem of determining which alcohol is obtained when 2-methylpropene reacts with water in the presence of sulfuric acid, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactant is 2-methylpropene (C5H10), which is an alkene.
- The other reactant is water (H2O), and sulfuric acid (H2SO4) is used as a catalyst.

2. **Understand the Mechanism**:
- When 2-methylpropene reacts with sulfuric acid, the acid donates a proton (H+) to the alkene, leading to the formation of a carbocation.
- The reaction can be represented as:
\[ \text{2-methylpropene} + H_2SO_4 \rightarrow \text{carbocation} + HSO_4^- \]

3. **Formation of Carbocation**:
- The double bond in 2-methylpropene can break, and a proton can add to one of the carbons.
- If H+ adds to the carbon with fewer substituents (the less substituted carbon), it will create a less stable carbocation (secondary).
- If H+ adds to the more substituted carbon, it will create a more stable tertiary carbocation.
- In this case, adding H+ to the more substituted carbon (the carbon with two methyl groups) leads to a tertiary carbocation:
\[ \text{(CH}_3)_2C^+CH_2 \]

4. **Nucleophilic Attack by Water**:
- Water (acting as a nucleophile) will attack the positively charged carbon of the carbocation.
- This results in the formation of an oxonium ion:
\[ \text{(CH}_3)_2C(OH_2)^+CH_2 \]

5. **Deprotonation**:
- The oxonium ion will lose a proton (H+) to yield the final alcohol product.
- The resulting product is tertiary butyl alcohol (C4H10O):
\[ \text{(CH}_3)_3COH \]

6. **Identify the Product**:
- The final product is tertiary butyl alcohol, also known as 2-methyl-2-propanol.

7. **Check the Options**:
- Based on the options provided, the correct answer is the one that corresponds to tertiary butyl alcohol.

### Final Answer:
The alcohol obtained when 2-methylpropene reacts with water in the presence of sulfuric acid is **tertiary butyl alcohol**.