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The perimeter of a quadrant of a circle ...

The perimeter of a quadrant of a circle of radius 'r' is :

A

`(pi r)/(2)`

B

`2 pi r`

C

`(r)/(2) [pi + 4]`

D

`2 pi r + (r)/(2)`

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The correct Answer is:
To find the perimeter of a quadrant of a circle with radius 'r', we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Quadrant**: A quadrant is one-fourth of a circle. It is formed by drawing two radii from the center of the circle to the circumference, creating a right angle (90 degrees). 2. **Identify the Components of the Perimeter**: The perimeter of the quadrant consists of: - The two straight sides (the radii) which are both equal to 'r'. - The curved part, which is one-fourth of the circumference of the circle. 3. **Calculate the Length of the Curved Part**: - The circumference of a full circle is given by the formula: \[ C = 2\pi r \] - Since we only need one-fourth of the circle (the curved part of the quadrant), we divide the circumference by 4: \[ \text{Curved Length} = \frac{2\pi r}{4} = \frac{\pi r}{2} \] 4. **Add the Lengths Together**: - The total perimeter (P) of the quadrant is the sum of the lengths of the two straight sides and the curved part: \[ P = r + r + \frac{\pi r}{2} \] - Simplifying this gives: \[ P = 2r + \frac{\pi r}{2} \] 5. **Factor Out 'r'**: - To express the perimeter in a more compact form, we can factor out 'r': \[ P = r \left(2 + \frac{\pi}{2}\right) \] ### Final Result: Thus, the perimeter of a quadrant of a circle with radius 'r' is: \[ P = r \left(2 + \frac{\pi}{2}\right) \]
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