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An arc of length of length 19 cm of a ci...

An arc of length of length 19 cm of a circle of radius 30 cm, subtends an angle `theta` at the centre O. The value of `theta` is:

A

`30^(@)`

B

`37^(@)`

C

`45^(@)`

D

`52^(@)`

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AI Generated Solution

The correct Answer is:
To find the angle \(\theta\) subtended at the center of a circle by an arc of length 19 cm, we can use the formula for the length of an arc: \[ L = \frac{\theta}{360} \times 2\pi r \] Where: - \(L\) is the length of the arc, - \(\theta\) is the angle in degrees, - \(r\) is the radius of the circle. ### Step-by-Step Solution: 1. **Identify the given values**: - Length of the arc, \(L = 19 \, \text{cm}\) - Radius of the circle, \(r = 30 \, \text{cm}\) 2. **Substitute the values into the arc length formula**: \[ 19 = \frac{\theta}{360} \times 2\pi \times 30 \] 3. **Calculate \(2\pi r\)**: - Using \(\pi \approx \frac{22}{7}\): \[ 2\pi \times 30 = 2 \times \frac{22}{7} \times 30 = \frac{1320}{7} \] 4. **Rewrite the equation**: \[ 19 = \frac{\theta}{360} \times \frac{1320}{7} \] 5. **Multiply both sides by \(360\)** to eliminate the fraction: \[ 19 \times 360 = \frac{\theta \times 1320}{7} \] 6. **Calculate \(19 \times 360\)**: \[ 19 \times 360 = 6840 \] 7. **Multiply both sides by \(7\)** to get rid of the denominator: \[ 6840 \times 7 = 1320\theta \] \[ 47880 = 1320\theta \] 8. **Solve for \(\theta\)**: \[ \theta = \frac{47880}{1320} \] 9. **Perform the division**: \[ \theta = 36.27 \] 10. **Round off to the nearest whole number**: \[ \theta \approx 37^\circ \] ### Final Answer: \(\theta \approx 37^\circ\)
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