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The value of p,q , r and s in balanced c...

The value of p,q , r and s in balanced chemical equation :
`pBaCl_(2)+qAl_(2)(SO_(4))_(3)torAlCl_(3)+sBaSO_(4)` are respectively

A

3,2,2,3

B

3,1,2,3

C

3,1,3,3

D

3,1,3,2

Text Solution

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The correct Answer is:
To solve the problem of balancing the chemical equation \( p \text{BaCl}_2 + q \text{Al}_2(\text{SO}_4)_3 \rightarrow r \text{AlCl}_3 + s \text{BaSO}_4 \), we will follow these steps: ### Step 1: Write the unbalanced equation The unbalanced equation is: \[ p \text{BaCl}_2 + q \text{Al}_2(\text{SO}_4)_3 \rightarrow r \text{AlCl}_3 + s \text{BaSO}_4 \] ### Step 2: Identify the number of atoms of each element - On the left side (reactants), we have: - Barium (Ba): \( p \) - Chlorine (Cl): \( 2p \) - Aluminum (Al): \( 2q \) - Sulfate (SO₄): \( 3q \) - On the right side (products), we have: - Aluminum (Al): \( r \) - Chlorine (Cl): \( 3r \) - Barium (Ba): \( s \) - Sulfate (SO₄): \( s \) ### Step 3: Set up equations based on the conservation of mass From the above counts, we can set up the following equations: 1. For Aluminum: \( 2q = r \) 2. For Chlorine: \( 2p = 3r \) 3. For Barium: \( p = s \) 4. For Sulfate: \( 3q = s \) ### Step 4: Solve the equations From equation 3, we can express \( s \) in terms of \( p \): \[ s = p \] Substituting \( s \) in equation 4 gives: \[ 3q = p \] Thus, we can express \( q \) in terms of \( p \): \[ q = \frac{p}{3} \] Now substituting \( q \) in equation 1: \[ 2\left(\frac{p}{3}\right) = r \] \[ r = \frac{2p}{3} \] Now substituting \( r \) in equation 2: \[ 2p = 3\left(\frac{2p}{3}\right) \] This simplifies to: \[ 2p = 2p \] This is always true, so we can choose a value for \( p \). ### Step 5: Choose a suitable value for \( p \) Let’s choose \( p = 3 \) (to keep \( q \) as a whole number): - Then, \( q = \frac{3}{3} = 1 \) - From \( r = \frac{2p}{3} = \frac{2 \times 3}{3} = 2 \) - And \( s = p = 3 \) ### Final values Thus, we have: - \( p = 3 \) - \( q = 1 \) - \( r = 2 \) - \( s = 3 \) ### Conclusion The values of \( p, q, r, \) and \( s \) in the balanced chemical equation are: - \( p = 3 \) - \( q = 1 \) - \( r = 2 \) - \( s = 3 \)

To solve the problem of balancing the chemical equation \( p \text{BaCl}_2 + q \text{Al}_2(\text{SO}_4)_3 \rightarrow r \text{AlCl}_3 + s \text{BaSO}_4 \), we will follow these steps: ### Step 1: Write the unbalanced equation The unbalanced equation is: \[ p \text{BaCl}_2 + q \text{Al}_2(\text{SO}_4)_3 \rightarrow r \text{AlCl}_3 + s \text{BaSO}_4 \] ### Step 2: Identify the number of atoms of each element - On the left side (reactants), we have: ...
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