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The sum of the first n terms of the seri...

The sum of the first n terms of the series
`1^2+2cdot2^3+3^2+2cdot4^2+5^2+2cdot6^2+…` is `(n(n+1))^2/2`, when n is even. When n is odd, the sum is

A

`(3n(n+1))/2`

B

`(n^2(n+1))/2`

C

`(n(n+1)^2)/4`

D

`[(n(n+1))/2]^2`

Text Solution

Verified by Experts

The correct Answer is:
B
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