If A=[(alpha,0,0),(0,alpha,0),(0,0,alpha...

If `A=[(alpha,0,0),(0,alpha,0),(0,0,alpha)]`, then |A||adjA| is equal to

A

`a^(3n)`

B

`a^(-3n)`

C

`-a^(3n)`

D

`2a^(3n)`

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The correct Answer is:

A

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