("sin" 8 theta "cos" theta -"sin" 6 thet...

`("sin" 8 theta "cos" theta -"sin" 6 theta "cos"3 theta)/("cos" 2 theta "cos" theta -"sin" 3 theta "sin" 4 theta) ` is equal to

A

`("sin" 7theta-"sin" 3 theta)/("cos" 7theta+"cos" 3 theta)`

B

`("sin" 7theta+"sin" 3 theta)/("cos" 7 theta+"cos" 3 theta)`

C

`("sin"7theta+"sin"3 theta)/("cos"7theta-"cos" 3 theta)`

D

None of these

Verified by Experts

The correct Answer is:

A

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