If cos (theta-alpha)=a and cos (theta-be...

If `cos (theta-alpha)=a `and` cos (theta-beta)`=b, then `sin^2(alpha-beta)+2ab cos(alpha-beta)` is equal to

A

`a^2+b^2`

B

`a^2-b^2`

C

`b^2-a^2`

D

`-a^2-b^2`

Verified by Experts

The correct Answer is:

A

Similar Questions

Explore conceptually related problems

If cos(theta-alpha)=a and cos(theta-beta)=b then the value of sin^(2)(alpha-beta)+2ab cos(alpha-beta)

It is given that cos(theta-alpha)=a, cos(theta-beta)=b What is sin^(2)(alpha-beta)+2abcos(alpha-beta) equal to ?

If cos (theta -alpha) =a, sin (theta - beta) =b, then cos ^(2) (alpha - beta) + 2 ab sin (alpha - beta) is equal to

If sin(theta+alpha)=a,cos^(2)(alpha+beta)=b, then sin(alpha-beta)=

If cos (theta - alpha) = a, cos (theta - beta) = b , then the value of sin^(2) (alpha - beta) + 2ab cos (alpha - beta) is

If cos(theta-alpha)=a,sin(theta-beta)=b, prove that a^(2)-2ab sin(alpha-beta)+b^(2)=cos^(2)(alpha-beta)

If sin(theta+alpha)=a and sin(theta+beta)=b, prove that cos2(alpha-beta)-4ab cos(alpha-beta)=1-2a^(2)-2b^(2)

If cos 3 theta = alpha cos theta + beta cos ^(3) theta, then (alpha, beta) =

It is given that cos(theta-alpha)=a, cos(theta-beta)=b What is cos(alpha-beta) equal to ?