If 3 cos x!=2 sin x, then the general so...

If `3 cos x!=2 sin x`, then the general solution of `sin^2 x-cos 2x=2 -sin 2x` is

A

`npi+(-1)^n pi/2,n in Z`

B

`(npi)/2,n in Z`

C

`(4n+- 1) pi/2, n in Z`

D

`(2n-1) pi, n in Z`

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The correct Answer is:

C

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