If x = asin theta and y = b cos theta, t...

If `x = asin theta` and `y = b cos theta`, then `(d^2y)/(dx^2)` is equal to

A

`a/b^2sec^2theta`

B

`-a/b^2sec^2theta`

C

`b/a^2sec^3theta`

D

`-b/a^2sec^3 theta`

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The correct Answer is:

D

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