Home
Class 12
MATHS
The velocity of telegraphic communicatio...

The velocity of telegraphic communication is given by `v=x^2 log(1/x)`, where x is the displacement. For maximum velocity, x is equal to

A

`e^(1//2)`

B

`e^(--1//2)`

C

`(2e)^(-1)`

D

`2e^(-1//2)`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Similar Questions

Explore conceptually related problems

The velocity of telegraphic comunication is given by v=x^(2) log (1//x) where x is the displacement for maximum velocity x equals to ?

The energy of a particle executing simple harmonic motion is given by E=Ax^2+Bv^2 where x is the displacement from mean position x=0 and v is the velocity of the particle at x then choose the correct statement(s)

Total energy of a particle executing oscillating motionis 3 joule and given by E=x^(2)+2x +v^(2)-2v Where x is the displacement from origin at x=0 and v is velocity of particle at x. Then choose the correct statements)

If the velocity of a moving particle vpropx^(n) , where x is the displacement then

The velocity of a particle moving on the x-axis is given by v=x^(2)+x , where x is in m and v in m/s. What is its position (in m) when its acceleration is 30m//s^(2) .

The speed v of particle moving along x-axis is given by v^(2) = 8bx - x^(2) - 12 b^(2) , where 'b' is a constant. Find amplitude, maximum velocity and time period of oscillation.

Statement-1 : In S.H.M., the motion is ‘to and fro’ and periodic. Statement-2 : Velocity of the particle (v) =omegasqrt(k^(2)-x^(2)) (where x is the displacement and k is amplitude)