S=sum(r=0)^(n-1) 1/sqrt(4n^2-r^2) as nra...

`S=sum_(r=0)^(n-1) 1/sqrt(4n^2-r^2) `as `nrarr oo` is equal to

A

`pi`

B

`pi/8`

C

`pi/6`

D

None of these

Verified by Experts

The correct Answer is:

C

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