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int cos(loge x) dx is equal to...

`int cos(log_e x) dx` is equal to

A

`1/2x[cos(log_2 x)+sin(log_ex)]+C`

B

`x[cos(log_ex)+sin (log_ex)]+C`

C

`1/2x[cos(log_ex)-sin(log_2 x)]+C`

D

`x[cos(log_ex)-sin(log_ex)]+C`

Text Solution

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The correct Answer is:
A
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