If In=int(logx)^n dx, then In+nI(n-1) i...

If `I_n=int(logx)^n dx, ` then` I_n+nI_(n-1)` is equal to

A

`x(logx)^n`

B

`(xlogx)^n`

C

`(logx)^(n-1)`

D

`n(logx)^n`

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The correct Answer is:

A

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