If x "sin"(y/x) dy=[y "sin" (y/x)-x]dx a...

If x `"sin"(y/x) dy=[y "sin" (y/x)-x]dx` and `y(1) =pi/2`, then the value of `"cos" (y/x)` is

A

x

B

1/x

C

logx

D

`e^x`

Verified by Experts

The correct Answer is:

C

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