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If P =P=[[sqrt3//2,1//2],[-1//2,sqrt3//2...

If P =`P=`[[sqrt3//2,1//2],[-1//2,sqrt3//2]]`, `A=`[[1,1],[0,1]]` and Q = `PAP^T`, then `P^TQ^2005P` is equal to

A

`[[1, 2005],[0,1]]`

B

`[[1, 2005],[2005,1]]`

C

`[[1, 0],[2005,1]]`

D

`[[1, 0],[0,1]]`

Text Solution

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The correct Answer is:
A
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