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int cosec (x-a) cosec x dx is equal to...

`int` cosec (x-a) cosec x dx is equal to

A

`-1/sina log [sinx coses (x -a)sin x]+C`

B

`-1/sina log [sin(x-a)sinx]+C`

C

`1/sina log [sin(x-a) cosec x]+C`

D

`1/sina log [sin(x-a)sinx]+C`

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • int"cosec"(x-a)"cosec"xdx is equal to

    A
    `(-1)/(sina)log|sinx"cosec "(x-a)|+C`
    B
    `(-1)/(sina)log[sin(x-a)sinx]+C`
    C
    `(1)/(sina)log[sin(x-a)"cosec x"]+C`
    D
    `(1)/(sina)log[sin(x-a)sinx]+C`

  • int sec^(4)x cosec^(2)x dx is equal to

    A
    `tan^(2)x+2tan x-cot x+c`
    B
    `(tan^(3)x)/(3)+2tan x-cot x+c`
    C
    `(tan^(2)x)/(2)+2tan x-cot x+c`
    D
    `(tan^(2)x)/(2)+2tan x-2cot x+c`

  • int(1-cosx)cosec^(2)x dx is equal to

    A
    `"tan" x/2+c`
    B
    `-"cot"x/2+c`
    C
    `2"tan"x/2+c`
    D
    `-2"cot"x/2+c`

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    int(1)/(tanx+cotx+secx+"cosec "x)dx is equal to

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