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If n=1,2,3,…, then cos alpha cos 2 alpha...

If n=1,2,3,…, then `cos alpha cos 2 alpha cos 4 alpha… cos2^(n-1)alpha` is equal to

A

`(sin2nalpha)/(2nsinalpha)`

B

`(sin2^nalpha)/(2^nsin2^(n-1)alpha)`

C

`(sin4^(n-1)alpha)/(4^(n-1)sinalpha)`

D

`(sin2^nalpha)/(2^nsinalpha)`

Text Solution

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The correct Answer is:
D
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