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A cylindrical bucket of height 36 cm and...

A cylindrical bucket of height 36 cm and radius 21 cm is filled with sand. The bucket is emptied on the ground and a conical heap of sand is formed, the height of the heap being 12 cm. The radius of the heap at the base is:

A

63cm

B

53cm

C

56cm

D

66cm

Text Solution

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The correct Answer is:
To find the radius of the conical heap of sand formed when the cylindrical bucket is emptied, we can follow these steps: ### Step 1: Calculate the Volume of the Cylinder The volume \( V \) of a cylinder is given by the formula: \[ V = \pi r^2 h \] where \( r \) is the radius and \( h \) is the height. Given: - Height of the cylinder \( h = 36 \) cm - Radius of the cylinder \( r = 21 \) cm Substituting the values into the formula: \[ V = \pi (21)^2 (36) \] Calculating \( (21)^2 \): \[ (21)^2 = 441 \] Now substituting back: \[ V = \pi \times 441 \times 36 \] Calculating \( 441 \times 36 \): \[ 441 \times 36 = 15996 \] Thus, the volume of the cylinder is: \[ V = 15996\pi \text{ cm}^3 \] ### Step 2: Set Up the Volume of the Cone The volume \( V \) of a cone is given by the formula: \[ V = \frac{1}{3} \pi R^2 H \] where \( R \) is the radius of the base of the cone and \( H \) is the height of the cone. Given: - Height of the cone \( H = 12 \) cm Since the volume of the sand remains the same, we can equate the volume of the cylinder to the volume of the cone: \[ 15996\pi = \frac{1}{3} \pi R^2 (12) \] ### Step 3: Simplify the Equation We can cancel \( \pi \) from both sides: \[ 15996 = \frac{1}{3} R^2 (12) \] This simplifies to: \[ 15996 = 4 R^2 \] ### Step 4: Solve for \( R^2 \) To isolate \( R^2 \), we multiply both sides by \( \frac{1}{4} \): \[ R^2 = \frac{15996}{4} \] Calculating \( \frac{15996}{4} \): \[ R^2 = 3999 \] ### Step 5: Calculate \( R \) Now, we take the square root of both sides to find \( R \): \[ R = \sqrt{3999} \] Calculating \( \sqrt{3999} \) gives approximately: \[ R \approx 63.245 \] Rounding to the nearest whole number, we find: \[ R \approx 63 \text{ cm} \] ### Conclusion The radius of the conical heap of sand is approximately \( 63 \) cm. ---
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