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A particle of mass m is projected with v...

A particle of mass m is projected with velocity v making an angle of `45^@` with the horizontal .The magnitude of the angular momentum of the projectile about the point of projection when the particle is at maximum height is :

A

Zero

B

`(mv^2)/(2sqrt(2)g)`

C

`(mv^3)/(4sqrt(2)g)`

D

`(mv^2)/(4sqrt(2) g)`

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