Home
Class 12
PHYSICS
PROBLEMS ON VERNIER & SCREW GAUGE...

PROBLEMS ON VERNIER & SCREW GAUGE

Text Solution

Verified by Experts

The correct Answer is:
NA
NA
Promotional Banner

Similar Questions

Explore conceptually related problems

ZERO ERROR OF SCREW GAUGE

Understanding Zero Error|Zero Error In A Vernier Caliper|Positive Zero Error|Negative Zero Error|Practice Exercise|Screw Gauge|Pitch Of A Screw Gauge|Least Count Of A Screw Gauge|Principle Of Screw Gauge|Method To Use Screw Gauge|Zero Error In A Screw Gauge|Positive Zero Error|Negative Zero Error|Practice Exercise|Summary

Vernier|| Screw Gauge|| Searlis Method and all Other Physics Experiments

( A ) Vernier callipers with 20 divisions on sliding scale, coinciding with 19 main scale divisions ( B ) A screw gauge of pitch 1 mm and 100 divisons on the circular scale ( C ) An optical instrument that can measure length to within a wavelength of light Out of A , B and C the most precise devide for measuring length is

A vernier calipers and a screw gauge have the same least count and zero error with the difference that the vernier calipers has positive zero error and the screw gauge has negative zero error. The number of circular scale divisions on the screw gauge is twice the number of vernier scale divisions on the vernier calipers and the pitch of the screw gauge is 1mm. If the vernier coinciding division and the circular are 3 and 97, respectively then find the number of vernier scale divisions on the vernier calipers.

Measuring Intruments | Screw Gauge | Least count of screw gauge

Consider a Vernier callipers in which each 1cm on the main scale is divided into 8 equal divisions and a screw gauge 5 divisions of the Vernier scale coincide with 4 divisions on the main scale and in the screw gauge, one complete rotation of the circular scale moves it by two divisions on the linder scale. Then:

The circular scale of a screw gauge has 200 divisions. When it is given 4 complete rotations, it moves through 2mm . The least count of the screw gauge is