`int(tan y)/(cos y)dy`

((ln (sec x + tan x)) / (cos x) dx = ((ln (sec y + tan y)) / (cos y) dy

If int_(y)^(y)cos t^(2)dt=int_(0)^(x^(2))(sin t)/(t)dx, the prove that (dy)/(dx)=(2sin x^(2))/(x cos y^(2))

If (sin x)^(y)=(cos y)^(x), prove that (dy)/(dx)=(log cos y-y cot x)/(log sin x+x tan y)

(sin x)^(y)=(cos y)^(x),quad prove that (dy)/(dx)=(log cos y-y cot x)/(log sin x+x tan y)

If (sin x)^(y)=(cos y)^(x), prove that (dy)/(dx)=(log cos y-y cot x)/(log sin x+x tan y)

(dy) / (dx) = (sin x-sin y) (cos x) / (cos y)

Solve the differential equation (dy)/(dx)=(tan x)/(y+sin y)

IFof 1+ (x tan y-sec y) (dy) / (dx) = 0

int (dy) / (y (3y-2))

solved the differential equation tan y(dy)/(dx)+tan x=cos y cos^(2)x