If lines are perpendicular, then find the value of k.

If the lines x+(a-1)y+1=0 and 2x+a^(2)y-1=0 are perpendicular,then find the value of a.

If the lines (x-1)/(-3)=(y-2)/(2k)=(z-3)/(2)(x-1)/(3k)=(y-1)/(1)=(z-6)/(-5) are perpendicular,find the value of k.

If the straight lines 2x+ 3y -3=0 and x+ky +7 =0 are perpendicular, then the value of k is

If the lines (x+1)/(-3)-(y+2)/(2k)-(z-3)/(2) and (x-1)/(3k)-(y+5)/(1)-(z+6)/(7) are perpendicular, then the value of k is

If the lines x−2/1=y−2/1=2 − z/k and x−1/k=4 −y/1=z−5/2 are perpendicular to each other, then the value of k is

If the lines (x -1)/(-3) = (x - 2)/(2k) = (z - 3)/(2) and (x - 1)/(3k ) = (y -1)/(1) = (z - 6)/(-5) are perpendicular to each other, then the value of k is ,

The two lines 5x + 3y + 7 = 0 and kx - 4y + 3 = 0 are perpendicular to the same line . Find the value of k .

If the lines (x-1)/(-3)=(y-2)/(-2y)=(z-3)/(2) and (x-1)/(k)=(y-2)/(1)-(z-3)/(5) are perpendicular,find the value of k and hence find the equation of plane containing these lines.

The locus of midpoints of the perpendiculars drawn from points on line x=2y to the line x=y is L_(1) .Suppose (h,k) lies on L_(1) .If line L_(2) passing through the points (h,k) and (4, 3) is perpendicular to L_(1) ,then the value of 7h+5k is