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0.7 g of iron reacts directly with 0.4 g...

`0.7 g` of iron reacts directly with `0.4 g` of sulphur to form ferrous sulphide. If `2.8 g` of iron is dissolved in dilute `HCl` and excess of sodium sulphide solution is added, `4.4 g` of iron sulphide is precipitated. Prove the law of constant composition.

Text Solution

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The ratio of the weight of iron and sulphur in the first sample of the compound is `Fe : S : : 0.7 : 0.4` or `7 : 4`.
According to the second experiment, `2.8 g` or iron gives `4.4 g` ferrous sulphide, or `2.8 g Fe` combines with `S = 4.4 - 2.8 = 1.6 g`
Therefore, the ratio of the weights of `Fe : S : : 2.8 : 1.6` or `7 : 4`.
Since the ratio of the weights of the two elements is same both the cases, the law of constant composition is true.
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