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P and Q are two element that form P(2) Q...

`P` and `Q` are two element that form `P_(2) Q_(3)` and `PQ_(2)`. If 0.15 mole of `P_(2) Q_(3)` weighs 15.9g and 0.15 mole of `PQ_(2)` weighs `9.3 g`, what are the atomic weights of `P` and `Q`?

Text Solution

Verified by Experts

Let the atomic weights of `P` and `Q` are `a` and `b`, respectively
`:'` Molecular weight of `P_(2) Q_(3) = 2a + 3b`
and molecular weigths of `PQ_(2) = a + 2b`
Now given that 0.15 mol `P_(2) Q_(3)` weight `15.9 g`
`(2a + 3b) = (15.9)/(0.15)` `( :' ("Weight")/("Molecular weigth") = "Mole")`
Similarly, `a + 2b = (9.3)/(0.15)`
Solving these two equations
`{:(b = 18),(a = 26):}`
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