Concentrated `HNO_(3)` is 69% by mass of nitric acid. Calculate the volume of the solution which contains `23 g` of `HNO_(3)`. (Density of concentrated `HNO_(3)` solution is `1.41 g ml^(-1))`

Explanation

`69 g NHO_(3) = 100 g` of solution
`23 g of HNO_(3) = (100)/(69) xx 33.3 g`
Volume of solution `= (33.3)/(1.41) = 23.6 mL`