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A 6.90 M solution of KOH contains 30% by...

A `6.90 M` solution of `KOH` contains 30% by weight of `KOH`. Calculate the density of the solution.

Text Solution

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`M = (% "by weighy" xx 10 xx d)/(Mw_(2))`
`6.9 = (30 xx 10 xx d)/(56)`
`d = 1.288 g mL^(-1)`
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