`3.2 g` sulphur combines with `3.2 g` of oxygen, to from a compound in one set of conditions. In another set of conditions `0.8 g` of sulphur combines with `1.2 g` of oxygen to form another compound. State the law illustrated by these chemical combinations.

Answer

A

Explanation

First case
`3.2 g` of `S` combines with `3.2 g of O_(2)`
`1 g` of `S` combines with `= 1 g of O_(2)`
Second case
`0.8 g` of `` combines with `1.2 g of O_(2)`.
`1 g` of `S` combines with `= (1.2)/(0.8) = 1.5 g of O_(2)`
Thus, the ratio of the `O_(2)` in both cases which combines with a fixed mass `(1 g)` of `S = 1 : 15` or `2 : 3`, which is a simple whole number ratio, and hence the law of multiple porportion is verified.