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KCL contains 52 % of potassium, Kl conta...

`KCL` contains 52 % of potassium, `Kl` contains 23.6% of potassium, and `ICI` contains 77.8% of iodine. Show that the above data is in agreement with the law of reciprocal proportions.

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The correct Answer is:
A
`KCl = 52^ K, 48% Cl`
`Kl = 23.6% K, 76.4% I`
`ICI = 77.8% I, 22.2% Cl`
In `KCl : 48 g of Cl` reacts with `52 g of K`.
`1 g of Cl` react with `= (52)/(48) = 1.08 of K`
In `ICI : 22.2 g of Cl` reacts with `77.8 g of I`
`1 g of Cl` reacts with `= (77.8)/(22.2) g of = 3.5 of I`
Ratio of `K` and `I` in `KCl` and `ICI` which reacts with fixed mass of `Cl (1 g) = 1.08:3.5 = (1.08)/(1.08) = (3.5)/(1.08) = 1 : 3.2`
These of `KI = 23.6:76.4 = (23.6)/(23.6) : (76.4)/(23.6) = 1 : 3.2`
These two ratios are `= (1)/(1) : (3.2)/(3.2) = 1 : 1`
This prove the law of reciprocal proportions.
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