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Find the weight of H(2) SO(4) in 1200 mL...

Find the weight of `H_(2) SO_(4)` in `1200 mL` of a solution of `0.2 N` strength.

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The correct Answer is:
A
`Mw` of `H_(2) SO_(4) = 2 xx 1 + 32 + 16 xx 4 = 98 g`
`Ew = (W_(2) xx 1000)/(Ew_(2) xx V_(sol)("in" mL))`
`0.2 = (W_(2) xx 1000)/(49 xx 1200) implies W_(2) = 11.76 g`
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