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If 4 g NaOH are dissolved in 100 mL of a...

If `4 g NaOH` are dissolved in `100 mL` of aqueous solution, what will be the differnce in its normality and molarity?

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The correct Answer is:
A
`(Mw of NaOH = 23 + 16 + 1 = 40)`
`M = (W_(2) xx 1000)/(Mw_(2) xx V_(sol)) = (4 xx 1000)/(40 xx 100) = 1`
Since `NaOH` is monobasic acid it normality and molarity will be same)
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