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The percentage composition (by weight) o...

The percentage composition (by weight) of a solution is `45% X, 15% Y`, and `40% Z`. Calculate the mole fraction of each component of the solution. (Molecular mass of `X = 18, Y = 60`, and `Z = 60)`

Text Solution

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The correct Answer is:
A, B, C
`X = 45%, n_(1) = (45)/(18) = 2.5`
`Y = 15%, n_(2) = (15)/(60) = 0.25`
`Z = 40%, n_(3) = (40)/(60) = 0.666`
`X_(1) = (n_(1))/(n_(1) + n_(2) + n_(3)) = (2.5)/(2.5 + 0.25 + 0.666)`
`= (2.5)/(3.146) = 0.73`
`X_(2) = (n_(2))/(n_(1) + n_(2) + n_(3)) = (0.25)/(3.146) = 0.073`
`X_(3) = [1 - (X_(1) + X_(2))] = (1 - 0.73 - 0.073) = 0.195`
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