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Cisplation is used an anticancer agent f...

Cisplation is used an anticancer agent for the treatment of solid tumors, and its prepared as follows:
`underset({:("Potassium tetra"),("Chloro platinate"):})(K_(2)[PtCl_(4)]) + 2NH_(3) rarr underset("Ciplatin")([Pt(NH_(3))_(2) Cl_(2)]) + 2KCl`
Given `83.0 g` of `K_(2) [PtCl_(4)]` is used with `83.0 g` of `NH_(3)`.
Atomic weights: `K = 39 , Pt = 415, Cl = 35.5 N = 14]`
The number of mol of `K_(2) [PtCl_(4)]` and `NH_(3)` used, respectively, are

A

0.1,0.2

B

0.2,0.04

C

0.3,0.6

D

0.03,0.06

Text Solution

Verified by Experts

The correct Answer is:
B
Mol of `K_(2) [PtCl_(4)]` consumed `= 0.2 "mol"`
= mol of cisplatin
`NH_(3)` consumed `= 2 xx 0.2 = 0.4 "mol"`.
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